ADOPTED LEVELS, GAMMAS for 6Li

Authors: Hu, Tilley, Kelley Et Al. |  Citation: Nucl. Physics A708, 3 (2002) |  Cutoff date: 23-Aug-2001 

 Full ENSDF file | Adopted Levels (PDF version) 


Q(β-)=-4288 keV 6S(n)= 5.66×103 keV 5S(p)= 4433 keV 20Q(α)= -1474 keV
Reference: 2012WA38

References:
  A  6He β- decay  B  3He(3H,X)
  C  4He(d,d)  D  6Li(E,E’)
  E  6Li(π++’),6Li(π--’)  F  6Li(p,p’)
  G  6Li(d,d)  H  6Li(3He,3He)
  I  6Li(α,α)  J  6Li(6Li,X)
  K  6Li(12C,12C)  L  7Li(γ,n),7Li(γ,PPI-)
  M  7Li(p,d),7Li(p,PN)  N  7Li(d,t)
  O  7Li(3He,α),7Li(3He,DA)  P  9Be(p,α)
  Q  9Be(t,6He)  R  9Be(3He,6Li)
  S  10B(d,6Li)  T  10B(3He,7Be)
  U  12C(α,10B),12C(α,DA)  V  10B(α,8Be)
  W  6Li(γ,γ’) 






E(level)
(keV)
XREFJπ(level) T1/2(level)E(γ)
(keV)
M(γ)
      0.0AB DEFGHIJKLMNO QRSTUVW 1+ STABLE   
   2186 2  BCDEFGHIJKLMNOPQRSTUV  3+ 24 keV 2 
% IT = ?
% α = ?
  2186
E2
   3562.88 10  B DEFGH J LMNOPQ     W 0+ 8.2 eV 2 
% IT = ?
  3561.75
M1
   4312 22  BCDEFG   K MNOP    U   2+ 1.30 MeV 10 
% IT = ?
% α = ?
  4310
E2
   5366 15  B D F      MNOP R      2+ 541 keV 20 
% IT = ?
% n = ?
% p = ?
% α = ?
  5363
M1
      5.65E3 5   C  F    K   OP R      1+ 1.5 MeV 2 
% α = ?
  
     15.8E3? B                      3+ 17.8 MeV 8 
% α = ?
  
  17985 25  B                      2- 3.012 MeV 7 
% IT = ?
% 3H = ?
  
     21.5E3? B                      0- % 3H = ?
  
     23E3 2 ? BC                     4+ 12. MeV 2 
% α = ?
  
  24779 54  B                      3- 6.75 MeV 11 
% IT = ?
% n = ?
% 3H = ?
  
  24890 55  B                      4- 5.32 MeV 11 
% IT = ?
% n = ?
% 3H = ?
  
E(level)
(keV)
XREFJπ(level) T1/2(level)E(γ)
(keV)
M(γ)
  26590 65  B                      2- 8.68 MeV 13 
% IT = ?
% n = ?
% 3H = ?
% α = ?
  
     31E3? B                      (3+) % 3H = ?
% α = ?
  

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Additional Gamma Data:











E(level)
(keV)
Jπ(level)T1/2(level)E(γ)
(keV)
MultipolarityAdditional Data
   2186 3+ 24 keV 2 
% IT = ?
% α = ?
  2186E2B(E2)(W.u.)=16.5 13
   3562.88 0+ 8.2 eV 2 
% IT = ?
  3561.75M1B(M1)(W.u.)=8.62 18
   4312 2+ 1.30 MeV 10 
% IT = ?
% α = ?
  4310E2B(E2)(W.u.)=6.8 35
   5366 2+ 541 keV 20 
% IT = ?
% n = ?
% p = ?
% α = ?
  5363M1B(M1)(W.u.)=8.3×10-2 15

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Additional Level Data and Comments:

E(level)Jπ(level)T1/2(level)Comments
     15.8E33+ 17.8 MeV 8 
% α = ?
T=0
From 1988Aj01.
  179852- 3.012 MeV 7 
% IT = ?
% 3H = ?
T=1
Previously reported as Ex=21.0 MeV (1988Aj01).
     21.5E30- % 3H = ?
T=1
From 1988Aj01.
     23E34+ 12. MeV 2 
% α = ?
T=0
From 1988Aj01.
  247793- 6.75 MeV 11 
% IT = ?
% n = ?
% 3H = ?
T=1
Previously reported as Ex=26.6 MeV 4, t=0(1988Aj01).

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