The bandhead energies for the two-particle states in the doubly odd actinide nucleus ${}_{95}{}^{246}{}_{}{}^{}\mathrm{Am}_{151}^{}{}_{}{}^{}$ are calculated involving single particle states up to a summed energy ($E_{\mathrm{p}}+E_{\mathrm{n}}$) up to 300 keV based on an evaluation of the zero range residual interaction energy contribution. The results are compared with the available experimental data. It is concluded that the ground state is the high spin isomer with $K^{\pi }=7^{-}$ corresponding to the configuration {${\frac{5}{2}}^{+}{\mathrm{}\left[642\right]\mathrm{}}_{\mathrm{p}}:{\frac{9}{2}}^{-}{\mathrm{}\left[734\right]\mathrm{}}_{\mathrm{n}}$} with the $K^{\pi }=2^{-}$ of the same configuration as the low spin isomer at an excitation energy of (30 ± 10) keV. The $K^{\pi }=2^{+}\{{\frac{5}{2}}^{-}{\mathrm{}\left[523\right]\mathrm{}}_{\mathrm{p}}:{\frac{9}{2}}^{-}{\mathrm{}\left[734\right]\mathrm{}}_{\mathrm{n}}\}$ bandhead is predicted to lie at about the same energy as the $K^{\pi }=2^{-}$ state. Predictions are made in all regarding the expected location of twelve two-particle states (six Gallagher-Moszkowski pairs).

[NUCLEAR STRUCTURE Odd-odd nucleus ${}_{}{}^{246}{}_{}{}^{}\mathrm{Am}$, two-particle bandhead energies from residual interaction calculations, configuration assignments.]

• Received 20 September 1983

DOI:https://doi.org/10.1103/PhysRevC.29.1556