211AT 211RN EC DECAY (14.6 H) 1972AS11,1972AS12 13NDS 201306
211AT H TYP=FUL$AUT=B. SINGH, S. SINGH, H.X. Nguyen and M. Patial$
211AT2 H CIT=NDS 114, 661 (2013)$CUT=28-FEB-2013$
211AT c The decay scheme proposed is that of 1972As11 and is based on
211AT2c energy fit and extensive coincidence data.
211AT c Others: 1990Ve05 and 1985BuZT (|g|g(|q)); 1970Be37 (E|g,I|g);
211AT2c 1956St60 (ce).
211AT cE The electron capture branches have been deduced from I(|g+ce)
211AT2cE balances on the adopted decay scheme.
211AT cE $Intensity balance is negative (-4.3 {I21}) for 947 level
211AT cG Unless noted otherwise, all data are from 1972As11.
211AT cG The ce spectra measured by 1972As11, 1972As12 were normalized
211AT2cG to the |g spectra through |a(K)(442.2|g)=0.02955, the theoretical
211AT3cG value for an E2 transition.
211AT cG E(A)$|g ray tentatively assigned to decay of {+211}Rn or {+207}Po
211AT cG M(B)$The 946.7|g and 947.4|g ce(K) are not resolved; the measured
211AT2cG |a(K)exp(sum)=0.010 {I1} is consistent with M1 for 946.7|g and E2 for
211AT3cG 947.4|g.
211AT DG CC$ FROM BrIcc v2.3 (19-Sep-2012) 2008Ki07, "Frozen Orbitals" appr.
211AT cG MR$ From 1990Ve05, obtained from combined analysis of their |g|g(|q)
211AT2cG and previous ce data, unless otherwise stated
211AT DG CC$ FROM BrIcc v2.3 (9-Dec-2011) 2008Ki07, "Frozen Orbitals" appr.
211AT cL Spin assignments are taken from Adopted Levels where
211AT2cL specific arguments for these assignments, based on experimental
211AT3cL results, are listed. 1972As11, 1972As12 also consider shell-model
211AT4cL calculations and propose the spin sequence 7/2-,7/2-,5/2-,3/2-
211AT5cL and 1/2+ for the levels at 674.1, 866.0, 947.4, 1116.2 and
211AT6cL 2479.2 keV. The |g|g(|q) results reported in 1985BuZT,
211AT7cL however, rule out the 1/2(D)3/2(D+Q)5/2 sequence for the
211AT8cL (1362.9|g)(168.7|g) cascade if |d(168.7|g)=2.7 {I4} (the |d measured
211AT9cL in ce data).
211AT cL $1990Ve05 report |g|g(|q) results for ten cascades in
211AT2cL this decay. Their conclusions, in general, agree with those of
211AT4cL 1972As11, 1972As12, but do not agree with the results of 1985BuZT
211AT5cL for the (1362.9|g)(168.7|g) cascade.
211AT cL J$From Adopted Levels.
211RN P 0.0 1/2- 14.6 H 2 2892 7
211RN cP J,T$ From Adopted Levels of {+211}Rn
211RN cP QP$ From 2012Wa38
211AT N 0.625 20 0.726 17 1.377
211AT PN 3
211AT cN NR$from |SI(|g+ce to g.s.)=100
211AT cN BR$%|e=72.6 {I17} deduced from I|g in |a and |e decays (1972As11)
211AT2cN and the level schemes.
211AT G 1038.2 5 0.08 3 A
211AT G 1482.9 2 0.09 2 A
211AT G 1654.5 2 0.06 1 A
211AT G 1686.0 4 0.028 14 A
211AT G 1747.0 4 0.011 4 A
211AT G 1947.9 4 0.023 6 A
211AT G 1953.4 4 0.016 5 A
211AT G 2113.4 4 0.012 4 A
211AT G 2212.9 3 0.022 4 A
211AT G 2405.1 5 0.009 3 A
211AT G 2486.0 4 0.009 2 A
211AT G 2696.3 5 0.0036 12 A
211AT L 0.0 9/2-
211AT L 674.1 (7/2)-
211AT cL J$|g|g(|q) favors 7/2 over 9/2
211AT G 674.1 1 100 M1+E2 -0.65 6 0.0493 19 C
211AT cG $Ice(K)=4.6 {I3}
211ATS G KC=0.0398 16$LC=0.00724 24$MC=0.00172 6$
211ATS G NC=0.000445 15$OC=9.5E-5 3$PC=1.29E-5 5
211AT cG M$from |a(K)exp=0.046 {I3}
211AT L 866.0 (7/2)-
211AT cL J$|g|g(|q) favors 7/2 over 5/2 or 9/2
211AT G 191.8 1 2.0 1 M1(+E2) -0.06 18 1.90 8 C
211AT cG $Ice(K)=2.8 {I7}
211ATS G KC=1.54 8$LC=0.275 4$MC=0.0652 12$
211ATS G NC=0.0169 3$OC=0.00361 6$PC=0.000499 9
211AT cG M$from |a(K)exp=1.4 {I4}, K/L=7 {I4}; |a(L1)exp=0.22 {I6} (1972As12).
211AT G 866.0 1 17.5 9 (E2) 0.01025 C
211AT cG $Ice(K)=0.13 {I3}
211ATS G KC=0.00792 11$LC=0.001769 25$MC=0.000430 6$
211ATS G NC=0.0001113 16$OC=2.33E-5 4$PC=3.01E-6 5
211AT cG M$from |a(K)exp=0.0073 {I15}
211AT cG MR$>+12 or -|@
211AT L 947.4 (5/2)-
211AT cL J$|g|g(|q) favors 5/2 over 7/2
211AT G 947.4 1 36 4 (E2) 0.00859 BC
211ATS G KC=0.00671 10$LC=0.001427 20$MC=0.000345 5$
211ATS G NC=8.93E-5 13$OC=1.88E-5 3$PC=2.44E-6 4
211AT L 1116.2 (3/2)- 0.57 NS 4
211AT cL J$|g|g(|q) favors 3/2 over 5/2
211AT cL T$from (ce(K))|g(t) (1972As12)
211AT E 0.008 LT 3 LT 8.4 GT 3 LT ?
211ATS E EAV=361.9 31$CK=0.7894$CL=0.15566 6$CM+=0.05229 3
211AT cE TI$1 {I3} from intensity balance
211AT G 168.7 1 14.9 8 E2+M1 -2.9 4 1.12 6 C
211AT cG $Ice(K)=7.2 {I7}
211ATS G KC=0.44 7$LC=0.499 8$MC=0.1318 23$
211ATS G NC=0.0341 6$OC=0.00676 12$PC=0.000720 11
211AT cG M$from |a(K)exp=0.47 {I5}, K:L2:M+N=7.2 {I7}:4.6 {I4}:1.4 {I4};
211AT2cG |a(L12)exp=0.31 {I2} (1972As12); K/L=0.6 (1956St60)
211AT G 250.2 1 13.3 7 E2 0.232 C
211AT cG $Ice(K)=1.0 {I4}
211ATS G KC=0.1017 15$LC=0.0969 14$MC=0.0255 4$
211ATS G NC=0.00660 10$OC=0.001316 19$PC=0.0001419 20
211AT cG M$from |a(K)exp=0.08 {I3}; |a(L)exp=0.104 {I24}, L12/L3=3.5 {I19}
211AT2cG (1972As12); and from |g|g(|q) (1985BuZT)
211AT cG $|d(M3/E2)=-0.12 {I7} (1990Ve05)
211AT cG (250|g)(192|g)(|q): A{-2}=+0.18 {I6}, A{-4}=-0.15 {I11}
211ATxcG (1990Ve05)
211AT cG (250|g)(866|g)(|q): A{-2}=-0.179 {I20}, A{-4}=-0.02
211ATxcG {I4}(1990Ve05)
211AT G 442.2 1 51 3 E2 0.0454 C
211ATS G KC=0.0295 5$LC=0.01192 17$MC=0.00304 5$
211ATS G NC=0.000786 11$OC=0.0001601 23$PC=1.88E-5 3
211AT cG M$from K/L=1.9 {I5} (1956St60) and |g|g(|q) (1985BuZT) (theory:
211AT2cG K/L(E2)=2.45, K/L(M1)=5.70, K/L(M4)=1.82)
211AT cG (442|g)(674|g)(|q): A{-2}=+0.230 {I8}, A{-4}=-0.025 {I15}
211ATxcG (1990Ve05)
211AT L 1800.8 (3/2)-
211AT cL J$|g|g(|q) favors 3/2 over 5/2
211AT E 3.6 LT 7.8 GT 3.6 LT ?
211ATS E CK=0.7810 2$CL=0.1636 2$CM+=0.05547 6
211AT cE TI$1.6 {I20} from intensity balance
211AT G 684.7 1 1.3 1
211AT G 853.4 1 10.2 5 (M1+E2) -0.38 11 0.0310 17 C
211AT cG $Ice(K)=0.21 {I3}
211ATS G KC=0.0252 14$LC=0.00440 21$MC=0.00104 5$
211ATS G NC=0.000269 13$OC=5.7E-5 3$PC=7.9E-6 4
211AT cG M,MR$from |a(K)exp=0.021 {I3}. Also |d=-0.01 {I17} from |g|g(|q)
211AT cG (853|g)(947|g)(|q): A{-2}=+0.04 {I3}, A{-4}=-0.06 {I6}
211ATxcG (1990Ve05)
211AT G 934.7 1 8.1 4 (E2) 0.00882 C
211AT cG $Ice(K)=0.08 {I3}
211ATS G KC=0.00688 10$LC=0.001473 21$MC=0.000357 5$
211ATS G NC=9.22E-5 13$OC=1.94E-5 3$PC=2.52E-6 4
211AT cG M$from |a(K)exp=0.010 {I3}
211AT cG $|d(M3/E2)=+0.03 {I7}, >+32 or <-7 (1990Ve05); the latter two values
211AT2cG are unrealistic, as 934.7 transition is not expected to be pure M3
211AT cG (935|g)(866|g)(|q): A{-2}=-0.09 {I5}, A{-4}=-0.04 {I9}
211ATxcG (1990Ve05)
211AT G 1126.7 1 49 3 (E2) 0.00616 C
211AT cG $Ice(K)=0.26 {I5}
211ATS G KC=0.00489 7$LC=0.000962 14$MC=0.000231 4$
211ATS G NC=5.96E-5 9$OC=1.258E-5 18$PC=1.666E-6 24$IPC=3.94E-7 6
211AT cG M$from |a(K)exp=0.0053 {I10}
211AT L 1992.5 (5/2)-
211AT G 1044.7 4 0.13 4
211AT G 1318.3 1 0.28 3
211AT G 1992.7 2 1.11 6 C
211AT L 2062.9 1/2-,3/2-
211AT E 1.8 15 7.9 4 1.8 15 ?
211ATS E CK=0.7717 4$CL=0.17016 25$CM+=0.05816 10
211AT G 262.1 1 0.49 5 M1 0.798 C
211AT cG $Ice(K)=0.5 {I2}
211ATS G KC=0.647 9$LC=0.1148 17$MC=0.0272 4$
211ATS G NC=0.00703 10$OC=0.001506 22$PC=0.000208 3
211AT cG M$from |a(K)exp=1.0 {I4}; K/L=5.0 {I14} (1956St60)
211AT G 946.7 1 11 3 (M1) 0.0259 BC
211ATS G KC=0.0212 3$LC=0.00363 5$MC=0.000855 12$
211ATS G NC=0.000221 4$OC=4.75E-5 7$PC=6.57E-6 10
211AT G 1115.5 3 0.2 1 A ?
211AT cG E$an 1115.2|g is known in {+207}Po from {+207}At |e decay.
211AT L 2108.7 (3/2)-
211AT E 2 LE 7.8 GE 2 LE ?
211ATS E CK=0.7693 4$CL=0.1718 3$CM+=0.05884 12
211AT cE TI$0.5 {I15}, assuming I|g=1.5 {I1}.5 for 992.5|g
211AT G 116.0 1 0.20 2 M1(+E2) 0.65 LT 7.4 6 C
211AT cG $Ice(K)=0.20 {I2}
211ATS G KC=5.5 9$LC=1.39 24$MC=0.34 7
211ATS G NC=0.089 18$OC=0.018 4$PC=0.0023 3
211AT cG M,MR$from |a(K)exp=6.1 {I15}
211AT G 992.5 3 AP ?
211AT cG RI$tentative evidence for this |g ray from (370|g)(169|g) and
211AT2cG (370|g)(250|g) coincidences
211AT G 1242.9 2 0.15 3
211AT G 1435.1 2 0.15 2
211AT L 2128.7 (5/2-)
211AT E 0.79 12 8.15 7 0.79 12
211AT cE LOGFT$too low for |DJ=2, no transition
211ATS E CK=0.7682 5$CL=0.1726 3$CM+=0.05917 12
211AT G 1012.5 1 0.47 4
211AT G 1181.3 1 3.2 2 C
211AT G 2129.0 3 0.010 4 A ?
211AT L 2479.2 (1/2)+
211AT cL J$|g|g(|q) favors 1/2 over 3/2
211AT E 68 4 5.59 4 68 4
211ATS E CK=0.7253 19$CL=0.2030 13$CM+=0.0717 6
211AT G 350.5 1 0.88 6 (M2) 1.200 C
211AT cG $Ice(K)=0.6 {I2}
211ATS G KC=0.903 13$LC=0.224 4$MC=0.0555 8$
211ATS G NC=0.01449 21$OC=0.00308 5$PC=0.000416 6
211AT cG M$|a(K)exp=0.7 {I2}; K/L=6.3 {I18} (1956St60)
211AT G 370.5 1 3.0 2 E1 0.0201 C
211AT cG $Ice(K)=0.06 {I3}
211ATS G KC=0.01642 23$LC=0.00282 4$MC=0.000663 10$
211ATS G NC=0.0001703 24$OC=3.58E-5 5$PC=4.70E-6 7
211AT cG M$from |a(K)exp=0.02 {I1}
211AT G 416.4 1 7.7 4 E1 0.01561 C
211AT cG $Ice(K)<0.15
211ATS G KC=0.01278 18$LC=0.00216 3$MC=0.000508 8$
211ATS G NC=0.0001308 19$OC=2.75E-5 4$PC=3.64E-6 5
211AT cG M$from |a(K)exp<0.02
211AT G 678.4 1 64 3 (E1+M2) 0.23 5 0.014 4 C
211AT cG $Ice(K)=0.7 {I2}
211ATS G KC=0.011 3$LC=0.0020 6$MC=0.00049 14$
211ATS G NC=0.00013 4$OC=2.7E-5 8 $PC=3.7E-6 11
211AT cG M,MR$from |a(K)exp=0.011 {I3}. (M1+E2 also allowed by |a(K)exp, but
211AT2cG ruled out by the decay scheme).
211AT cG (678|g)(853|g)(|q): A{-2}=-0.10 {I4}, A{-4}=-0.02 {I8}
211ATxcG (1990Ve05)
211AT cG (678|g)(1127|g)(|q)+(1127|g)(674|g)(|q):
211AT2cG A{-2}=+0.066 {I9}, A{-4}=+0.006 {I15} (1990Ve05)
211AT G 1362.9 1 72 4 E1+M2 -0.12 3 0.0020418 C
211AT cG $Ice(K)=0.10 {I3}
211ATS G KC=0.00162 14$LC=0.00026 3$MC=6.0E-5 7$
211ATS G NC=1.56E-5 17$OC=3.3E-6 4$PC=4.6E-7 5$IPC=7.95E-5 13
211AT cG M$from |a(K)exp=0.0014 {I4}
211AT cG (1363|g)(442|g)(|q): A{-2}=-0.040 {I9}, A{-4}=+0.009 {I17}
211ATxcG (1990Ve05)
211AT DG (1363G)(442G)(THETA): A2=-0.068 8, A4=-0.014 15 (QUOTED
211AT2DG BY 1990Ve05 FROM A 1985 ^JINR PREPRINT P6-85-760, BY SAME AUTHORS AS
211AT3DG 1985BuZT)
211AT cG (1363|g)(250|g)(|q): A{-2}=-0.038 {I18}, A{-4}=-0.03 {I4}
211ATxcG (1990Ve05)
211AT DG (1363G)(250G)(THETA): A2=-0.079 9, A4=+0.001 19 (QUOTED
211AT2DG BY 1990Ve05 FROM A 1985 ^JINR PREPRINT P6-85-760, BY SAME AUTHORS AS
211AT3DG 1985BuZT)
211AT cG (1363|g)(169|g)(|q): A{-2}=-0.001 {I17}, A{-4}=+0.01 {I4}
211AT2cG (1990Ve05). The corresponding values from 1985BuZT disagree
211AT DG (1363G)(169G)(THETA): A2=+0.296 5, A4=+0.008 5 (QUOTED
211AT2DG BY 1990Ve05 FROM A 1985 ^JINR PREPRINT P6-85-760, BY SAME AUTHORS AS
211AT3DG 1985BuZT). THESE VALUES SEEM DISCREPANT SINCE DEDUCED MR(169)=0.46 2
211AT4DG DISAGREES WITH 2.8 4 FROM CE DATA AND 2.9 4 FROM GG(THETA) (1990Ve05)
211AT G 1531.8 3 0.10 5
211AT G 1805.0 2 0.26 5 [E3] 0.00528
211ATS G KC=0.00410 6$LC=0.000825 12$MC=0.000198 3
211ATS G NC=5.14E-5 8$OC=1.088E-5 16$PC=1.455E-6 21$IPC=9.61E-5 14
211AT L 2655.0 1/2,3/2
211AT E 5.1 6 6.08 7 5.1 6
211ATS E CK=0.626 9$CL=0.272 7$CM+=0.101 3
211AT G 176.0 1 0.14 3 [D,E2] 1.3 12
211AT G 592.3 1 0.58 5
211AT G 1538.8 2 10.4 11 C