In response to recent papers which suggest that a level around $9.5\text{MeV}$ in excitation in ${}^{10}\mathrm{Be}$ nucleus is its first $J^{\pi }T=3^{+}1$ state, the experimental results are presented which undoubtedly prove that it is the fourth $2^{+}1$ state. Recent observations that the state at $7.00\text{MeV}$ in ${}^{10}\mathrm{B}$ decays also into $\alpha +{}^6\mathrm{Li}*\left(2.19\text{MeV}\right)$ are interpreted as a strong evidence that it is the third $3^{+}0$ state of this nucleus. The structure of these states is discussed.

• Received 1 August 2003

DOI:https://doi.org/10.1103/PhysRevC.69.017303