Elsevier

Nuclear Physics A

Volume 143, Issue 1, 9 March 1970, Pages 97-108
Nuclear Physics A

Low-lying T = 2 states of 16O

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Abstract

The excitation energies of the lowest two T = 2 states in 16O are found to be 22.717±0.008 MeV (Γ < 30 keV) and 24.522 ±0.011 keV (Γ < 50 MeV) using the 14C(3He, n) reaction. These energies are in excellent agreement with elementary Coulomb energy calculations which are quite successful in other T = 2 and T = 32 isobaric multiplets. Double stripping angular distributions indicate that the 24.52 MeV state has Jπ = 2+. In a 12C(3He, n) measurement, the excitation energy of the fourth excited state of 14O has been determined to be 6.585±0.005 MeV. Some systematics of T = 2 and T = 32 levels are discussed.

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  • Cited by (0)

    Present address: Princeton University, Princeton, New Jersey.

    †††

    Supported in part by the National Science Foundation [GP-9114] at the California Institute of Technology

    ††

    Present address: Chalk River Nuclear Laboratories, Ontario, Canada.

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